Calculate the volume of oxygen required for complete combustion of 122 g of benzoic xylote.

2C6H5COOH + 15O2 = 14CO2 + 6H2O
n (C6H5COOH) = m / M = 122/122 = 1 mol
1/2 = x / 15
x = 15/2
x = 7.5 mol
V (O2) = Vm × n = 7.5 × 22.4 = 168 liters
Answer: 168 liters



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