Calculate the volume of oxygen required for complete combustion of 162 g of 1,3-butadiene.

univerkov | November 21, 2020 | education

С4H6 + 5.5O2 = 4CO2 + 3H2O
n (C4H6) = m / M = 162/54 = 3 mol
x / 5.5 = 3/1
x = 5.5 × 3
x = 16.5 mol
V (CO2) = Vm × n = 16.5 mol × 22.4 l / mol = 369.6 liters

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