Calculate the volume of oxygen required for complete combustion of 18.4 g glycerin under normal conditions.

The oxidation reaction of glycerol with oxygen is described by the following chemical reaction equation:

2C3H8O3 + 7O2 = 6CO2 + 8H2O;

7 moles of oxygen are reacted with 2 moles of glycerol. This synthesizes 6 mol of carbon monoxide.

Let’s calculate the available chemical amount of the glycerin substance.

M C3H8O3 = 12 x 3 + 8 + 16 x 3 = 92 grams / mol;

N C3H8O3 = 18.4 / 92 = 0.2 mol;

This reaction will require 0.2 x 7/2 = 0.7 mol of oxygen.

Let’s calculate the volume of oxygen. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 0.7 x 22.4 = 15.68 liters;