Calculate the volume of oxygen required for incomplete combustion of hydrogen sulfide

Calculate the volume of oxygen required for incomplete combustion of hydrogen sulfide if sulfur with a mass of 128 g is formed in the reaction.

The reaction of incomplete oxidation of hydrogen sulfide is described by the following chemical reaction equation.

2H2S + O2 = 2H2O + 2S;

2 mol of hydrogen sulfide reacts with 1 mol of oxygen. In this case, 2 mol of water and 2 mol of solid sulfur are synthesized.

Let’s calculate the chemical amount of synthesized sulfur.

To do this, we divide its weight by the weight of 1 mole of sulfur.

M S = 32 grams / mol; N S = 128/32 = 4 mol;

To get this amount of sulfur, you need 2 moles of oxygen.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V O2 = 2 x 22.4 = 44.8 liters;