Calculate the volume of oxygen required for the complete combustion of 8 liters of propane (C3H8, gas).

Given: V (C3H8) = 8 liters.
Determine: V (O2) -?
Solution:
1. Let’s compose the reaction equation:
C3H8 + 5O2 = 3 CO2 + 4H2O;
2. Let’s find the amount of substance С3Н8 according to the equation:
1 mol C3H8 – 22.4 L;
X mol – 8 l;
Hence, x = 8 * 1 / 22.4 = 0.357 mol.
3. We make the proportion: 0.357 mol / 1 mol = xY (O2) / 5 mol.
4. Let’s calculate: Y (O2) = 0.365 * 5/1 = 1.8 mol.
5. V (O2) = 1.8 mol * 22.4 = 40.32 L;
Answer: V (O2) = 40.32 liters.