Calculate the volume of oxygen required to burn 10 liters of hydrogen.

The reaction of burning hydrogen with the formation of water:

2H2 + O2 = 2H2O.

Let’s calculate the number of moles of hydrogen:

n (H2) = V / Vm = 10 / 22.4 = 0.446 mol.

The oxygen will be half as much according to the reaction equation.

n (O2) = n (H2) / 2 = 0.446 / 2 = 0.223 mol.

Accordingly, the volume of oxygen is:

V (O2) = n • Vm = 0.223 • 22.4 = 5 liters.

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