Calculate the volume of oxygen required to burn 10 liters of hydrogen.

The oxidation reaction of hydrogen with oxygen is described by the following chemical reaction equation:

H2 + ½ O2 = H2O2;

1/2 mole of oxygen is reacted with 1 mole of hydrogen. 1 mol of its oxide is synthesized.

Let’s calculate the available chemical amount of hydrogen.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N H2 = 10 / 22.4 = 0.446 mol;

This reaction requires 0.446 / 2 = 0.223 mol of oxygen.

Let’s calculate the volume of oxygen. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 0.223 x 22.4 = 4.995 liters;