Calculate the volume of oxygen required to burn 24 g carbon.

1. Let’s make the equation of the chemical reaction:
C + O2 = CO2.
2. Find the chemical amount of burned carbon:
n (C) = m (C) / M (C) = 24 g / 12 g / mol = 2 mol.
3. According to the reaction equation, we find the chemical amount of reacted oxygen, and then its volume (Vm is the molar volume, constant equal to 22.4 l / mol):
n (O2) = n (C) = 2 mol.
V (O2) = n (O2) * Vm = 2 mol * 22.4 L / mol = 44.8 L.
Answer: V (O2) = 44.8 liters.



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