Calculate the volume of oxygen required to burn 50 liters of acetylene.

Let’s execute the solution:
1. In accordance with the condition of the problem, we compose the equation:
V = 50 HP X l. -?
2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q – combustion of acetylene, carbon monoxide (4) and water are released;
2. Proportions:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H2) – 50 liters. hence, X mol (C2H2) = 1 * 50 / 22.4 = 2.23 mol;
2.23 mol (C2H2) – X mol (O2);
-2 mol -5 mol from here, X mol (O2) = 2.23 * 5/2 = 5.57 mol.
3. Find the volume of O2:
V (O2) = 5.57 * 22.4 = 124.77 liters.
Answer: for the combustion of acetylene, oxygen with a volume of 124.77 liters is required.