Calculate the volume of oxygen required to burn 6.4 g of sulfur.
| September 22, 2021 | education
1. Let’s write the equation of the chemical reaction:
S + O2 = SO2.
2. Find the chemical amount of sulfur:
n (S) = m (S) / M (S) = 6.4 g / 32 g / mol = 0.2 mol.
3. According to the reaction equation, we find the chemical amount of oxygen, and then its volume (Vm is the molar volume, constant equal to 22.4 l / mol):
n (O2) = n (S) = 0.2 mol.
V (O2) = n (O2) * Vm = 0.2 mol * 22.4 L / mol = 4.48 L.
Answer: V (O2) = 4.48 liters.
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