Calculate the volume of oxygen required to burn 8 liters of ethylene.

Given:
V (C2H4) = 8 l

To find:
V (O2) -?

1) Write the equation of a chemical reaction:
C2H4 + 3O2 => 2CO2 + 2H2O;
2) Calculate the volume of oxygen, guided by the Gay-Lussac law (the law of volumetric ratios, taking into account the coefficients in the reaction equation):
V (O2) = V (C2H4) * 3 = 8 * 3 = 24 HP

Answer: The volume of oxygen is 24 liters.



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