Calculate the volume of oxygen required to burn a 10 L portion of C2H2 acetylene.

Let’s execute the solution:
1.According to the condition of the problem, we write:
V = 10 liters. X l -?
2С2Н2 + 5О2 = 4СО2 + 2Н2О + Q – combustion of acetylene, heat, carbon dioxide and water are released;
2. Proportions:
1 mol of gas at normal level – 22.4 liters.
X mol (C2H2) – 10 liters. hence, X mol (C2H2) = 1 * 10 / 22.4 = 0.45 mol.
0.45 mol (C2H2) – X mol (O2);
-2 mol – 5 mol from here, X mol (O2) = 0.45 * 5/2 = 1.125 mol.
3. Find the volume of the original substance:
V (O2) = 1.125 * 22.4 = 25.2 liters.
Answer: for the combustion process, oxygen with a volume of 25.2 liters is required.