Calculate the volume of oxygen required to completely burn 67.2 liters of ethane.

univerkov | April 30, 2021 | education

Let us write the equation for the reaction of burning ethane.

2C2H6 + 7O2 = 4CO2 + 6H2O.

1 mole of any gas occupies a volume of 22.4 liters, which means the number of moles of ethane is.

n (C2H6) = V / 2 • Vm = 67.2 / 2 • 22.4 = 1.5 mol.

And according to the reaction equation, there is 7 times more oxygen.

n (O2) = 7 • n (C2H6) = 7 • 1.5 = 10.5 mol

The required volume of oxygen for the complete combustion of ethane.

V (O2) = n • Vm = 10.5 • 22.4 = 235.2 mol.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.