Calculate the volume of oxygen required to obtain 300 g of phosphorus oxide (P2O5).

The synthesis reaction of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. During the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus oxide weighing 300 grams.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

N P2 O5 = 300/142 = 2.113 mol;

To synthesize such an amount of oxide, you need to take 2.113 / 2 x 5 = 5.283 mol of oxygen.

Let’s calculate its volume.

To do this, multiply the amount of oxygen by the volume of 1 mole of gas.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 5.283 x 22.4 = 118.34 liters;