Calculate the volume of oxygen that is required to burn sodium with a mass of 13.8 g.

In accordance with the condition of the problem, we write the equation:
4Na + O2 = 2Na2O – oxidation reaction, sodium oxide obtained;
Let’s calculate the molar masses of sodium and oxygen:
M (Na) = 22.9 g / mol;
M (O2) = 32 g / mol.
Determine the amount of sodium moles if the mass is known:
Y (Na) = m / M = 13.8 / 22.9 = 0.6 mol.
We make the proportion:
0.6 mol (Na – X mol (O2);
-4 mol – 1 mol from here, X mol (O2) = 0.6 * 1/4 = 0.15 mol.
We find the volume of oxygen:
V (O2) = 0.15 * 22.4 = 3.36 liters.
Answer: the volume of oxygen is 3.36 liters.