Calculate the volume of oxygen that will result from the decomposition of 8.5 g of sodium nitrate.

The decomposition reaction of sodium nitrate is described by the following chemical reaction equation:

2NaNO3 = 2NaNO2 + O2;

From two moles of sodium nitrate, one mole of oxygen is formed.

Determine the molar amount of 8.5 grams of sodium nitrate.

Its molar mass is:

M NaNO3 = 23 + 14 + 16 x 3 = 85 grams / mol;

Let’s determine the amount of substance:

N NaNO3 = 8.5 / 85 = 0.1 mol;

During the reaction, 0.1 / 2 = 0.05 mol of oxygen is formed.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Determine the volume of oxygen:

V O2 = 0.05 x 22.4 = 1.12 liters;