Calculate the volume of oxygen under normal conditions that will be required for the combustion

Calculate the volume of oxygen under normal conditions that will be required for the combustion of hydrogen sulfide if sulfur with a mass of 64 grams is formed in the reaction

The reaction of incomplete oxidation of hydrogen sulfide is described by the following chemical reaction equation.

2H2S + O2 = 2H2O + 2S;

2 mol of hydrogen sulfide reacts with 1 mol of oxygen. In this case, 2 mol of water and 2 mol of solid sulfur are synthesized.

Let’s calculate the chemical amount of synthesized sulfur.

To do this, we divide its weight by the weight of 1 mole of sulfur.

M S = 32 grams / mol; N S = 64/32 = 2 mol;

To obtain such an amount of sulfur, 1 mole of oxygen is needed.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V O2 = 1 x 22.4 = 22.4 liters;