# Calculate the volume of ozone generated by passing an electric discharge through oxygen of 8.064 liters containing 16.7% impurities.

January 13, 2021 | education

| 1. Let’s find the volume of oxygen without impurities (100% – 16.7% = 83.3%):

8.064 L O2 – 100%

xl O2 – 83.3%

Hence, x = 8.064 * 83.3 / 100 = 6.72 l

2. Let’s compose the reaction equation:

3 O2 = 2 O3

According to the equation:

3 mol of oxygen, i.e. 67.2 l;

2 mol of ozone, i.e. 44.8 l.

3. Let’s calculate the volume of ozone, making up the proportion:

6.72 L O2 – x L O3

67.2 L O2 = 44.8 L O3

Hence, x = 6.72 * 44.8 / 67.2 = 4.48 l

Answer: V (O3) = 4.48 liters.

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