Calculate the volume of ozone generated by passing an electric discharge through oxygen of 8.064 liters containing 16.7% impurities.

1. Let’s find the volume of oxygen without impurities (100% – 16.7% = 83.3%):
8.064 L O2 – 100%
xl O2 – 83.3%
Hence, x = 8.064 * 83.3 / 100 = 6.72 l
2. Let’s compose the reaction equation:
3 O2 = 2 O3
According to the equation:
3 mol of oxygen, i.e. 67.2 l;
2 mol of ozone, i.e. 44.8 l.
3. Let’s calculate the volume of ozone, making up the proportion:
6.72 L O2 – x L O3
67.2 L O2 = 44.8 L O3
Hence, x = 6.72 * 44.8 / 67.2 = 4.48 l
Answer: V (O3) = 4.48 liters.