Calculate the volume of so2 formed by the reaction of 3.2 grams of excess copper with concentrated sulfate acid.

1.Calculate the amount of copper substance Cu according to the formula:

n = m: M, where M is molar mass.

M (Cu) = 64 g / mol.

n = 3.2 g: 64 g / mol = 0.05 mol.

2. We compose the equation of the reaction between copper and concentrated sulfuric acid, we find the quantitative ratios of copper and sulfur oxide.

1 mol of copper, reacting with 2 acids, forms 1 mol of SO2.

Cu + 2H2SO4 (conc) = СuSO4 + SO2 + 2H2O.

The substances are in a 1: 1 ratio, so the amounts of Cu and SO2 will be equal.

n (Cu) = n (SO2) = 0.05 mol.

3.Let’s find the volume of SO2 by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V (SO2) = 22.4 L / mol × 0.05 mol = 1.12 L.

Answer: V (SO2) = 1.12 liters.