Calculate the volume of sulfur oxide (lV) weighing 320 g.

Let’s find the amount of the substance SO2 – sulfur oxide (IV):

v (SO2) = m (SO2) / M (SO2) = 320/64 = 5 (mol)

Under normal conditions, 1 mole of any gas occupies a volume of 22.4 liters:

V = v * Vm, where Vm = 22.4 liters.

Thus, the volume of sulfur oxide (IV) is equal to:

V (SO2) = v (SO2) * Vm = 5 * 22.4 = 112 (l)

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