Calculate the volume of sulfur (VI) oxide that can be obtained by oxidizing 5.6 grams of sulfur if the product yield is 90%

The combustion reaction of sulfur is described by the following chemical reaction equation:

S + O2 = SO2;

From one mole of sulfur, one mole of its oxide is formed.

Find the amount of moles of sulfur that reacts.

The molar mass of sulfur is 32 grams / mol.

5.6 x 0.9 = 5.04 grams enters the reaction;

The amount of substance will be:

N S = 5.04 / 32 = 0.1575 mol;

The same amount of moles of sulfur oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of gas:

V SO2 = 0.1575 x 22.4 = 3.528 liters;