Calculate the volume of sulphurous gas that is formed during the firing of 485 kg

univerkov | August 9, 2021 | education

Calculate the volume of sulphurous gas that is formed during the firing of 485 kg of zinc blende containing 20% silicon oxide (IV) as an impurity.

1. Let’s compose the equation of a chemical reaction.

2ZnS + 3O2 = 2ZnO + 2SO2.

2. Find the amount of zinc sulfide reacted.

ω (ZnS) = 100% – ω (impurities) = 100% – 20% = 80%.

m (ZnS) = m (mixtures) * ω (ZnS) / 100% = 485000 g * 80% / 100% = 388000 g.

n (ZnS) = m (ZnS) / M (ZnS) = 388000 g / 98 g / mol = 3959.18 mol.

3. Using the reaction equation, we find the amount and then the volume of sulfur dioxide.

n (SO2) = n (ZnS) = 3959.18 mol.

V (SO2) = n (SO2) * Vm = 3959.18 mol * 22.4 l / mol = 88685.71 l.

Answer: V (SO2) = 88685.71 liters.

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