# Calculate the volume of the balloon filled with helium. would have a carrying capacity corresponding

Calculate the volume of the balloon filled with helium. would have a carrying capacity corresponding to the weight of a student, equal to 450 N. The weight of the shell and the gondola should be considered equal to the weight of the student.

Task data: P (shell and nacelle weight) = 450 N.

Constants: g (acceleration of gravity) = 9.81 m / s2; ρv (air density, n.o.) = 1.292 kg / m3; ρg (density of helium) = 0.1785 kg / m3.

The required volume of the balloon used is determined from the equality: Fa = Fтг + P.

ρw * g * V = ρg * g * V + P.

(ρv – ρg) * g * V = P.

V = P / ((ρv – ρg) * g).

Let’s calculate: V = 450 / ((1.292 – 0.1785) * 9.81) = 41.2 m3.

Answer: The minimum volume of the balloon used is 41.2 m3. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.