Calculate the volume of the product that was formed during the combustion of 64 g of sulfur in an excess of oxygen.

In this activity, you will need to write down the solution for the next problem.

First, you need to write down the reaction equation.

S + O2 = SO2.

Let’s determine the amount of sulfur substance. We use the following formula.

n = m / M.

Let’s determine the molar mass of sulfur.

M (S) = 32 g / mol.

n (S) = 64/32 = 2 mol.

Let’s make a proportion and determine the amount of substance of the resulting compound.

2 mol – x mol.

1 mol – 1 mol.

X = 2 * 1/1 = 2 mol of sulfur oxide.

Determine the volume of sulfur oxide.

n = V / Vm.

V = n * Vm = 2 * 22.4 = 44.8 liters.

This means that the volume of sulfur oxide is 44.8 liters.

Answer: 44.8 liters.