Calculate the volume of the reaction product formed during the combustion of 16 grams of sulfur.

S + O2 = SO2.

To solve the problem, we need the molar masses of the compounds: Mr (S) = 32 g / mol, Mr (SO2) = 64 g / mol. Obviously, from 32 g of sulfur, 64 g of sulfur oxide is formed during combustion. To find the mass of oxide formed from 16 g of sulfur, we will compose the proportion:

16 g – x g

32 g – 64 g

Hence x = 16 * 64/32 = 32 g. Then the amount of substance is equal to:

n = m / Mr = 32/64 = 0.5 mol. Knowing that the volume occupied by 1 mole of any gas under normal conditions is 22.4 liters, we find the volume of sulfur oxide:

V = 0.5 * 22.4 = 11.2 l.