Calculate the volume of the substance and the mass of the gas obtained by the interaction of sodium with water.

Given:
m (Na) = 46 g

To find:
V (gas) -?
n (gas) -?
m (gas) -?

1) Write the equation of a chemical reaction:
2Na + 2H2O => 2NaOH + H2 ↑;
2) Calculate the amount of substance Na:
n (Na) = m (Na) / M (Na) = 46/23 = 2 mol;
3) Determine the amount of substance H2:
n (H2) = n (Na) / 2 = 2/2 = 1 mol;
4) Calculate the volume H2:
V (H2) = n (H2) * Vm = 1 * 22.4 = 22.4 L;
5) Calculate the mass of H2:
m (H2) = n (H2) * M (H2) = 1 * 2 = 2 g.

Answer: The amount of substance H2 is 1 mol; volume – 22.4 liters; weight – 2 g.