Calculate the volume of water that needs to be evaporated from 200 kg of 60% sulfuric acid to obtain a 96% solution.

Given:
m1 solution (H2SO4) = 200 kg = 200000 g
ω1 (H2SO4) = 60%
ω1 (H2SO4) = 96%
ρ (H2O) = 1 g / ml

To find:
ΔV (H2O) -?

Decision:
1) Calculate the mass of H2SO4 (it will not change):
m (H2SO4) = ω1 (H2SO4) * m1 solution (H2SO4) / 100% = 60% * 200,000 / 100% = 120,000 g;
2) Calculate the mass of the new H2SO4 solution:
m2 solution (H2SO4) = m (H2SO4) * 100% / ω2 (H2SO4) = 120,000 * 100% / 96% = 125,000 g;
3) Calculate the mass of evaporated H2O:
Δm (H2O) = m1 solution (H2SO4) – m2 solution (H2SO4) = 200000 – 125000 = 75000 g;
4) Calculate the volume of evaporated H2O:
ΔV (H2O) = Δm (H2O) / ρ (H2O) = 75000 * 1 = 75000 ml = 75 liters.

Answer: The volume of H2O is 75 liters.