Calculate the volume required to burn 224 m3 of CH4 methane, if this produces carbon

Calculate the volume required to burn 224 m3 of CH4 methane, if this produces carbon monoxide (4) and water. Take the volume fraction of oxygen in the air as 21%.

1. Let’s compose the equation of the chemical reaction:

CH4 + O2 = CO2 + H2O.

2. Find the chemical amount of methane (Vm – molar volume, constant equal to 22.4 l / mol):

224 m3 = 224000 l.

n (CH4) = V (CH4) / Vm = 224000 L / 22.4 L / mol = 10000 mol.

3. According to the reaction equation, we find the amount and then the volume of oxygen:

n (O2) = n (CH4) = 10000 mol.

V (O2) = n (O2) * Vm = 10000 * 22.4 l / mol 224000 l.

4. Find the volume of air:

V (air) = V (O2) * 100% / ω (O2) = 224000 * 100% / 21% = 106666 l = 106.7 m3.

Answer: V (air) = 106.7 m3.