Calculate the volumes of hydrogen and carbon monoxide formed in the reaction: CH4 + H2O CO + H2 5 l 9 g x,

Given:
V (CH4) = 5 l
m (H2O) = 9 g

To find:
V (CO) -?
V (H2) -?

1) CH4 + H2O => CO + 3H2;
2) n (CH4) = V / Vm = 5 / 22.4 = 0.22 mol;
3) n (H2O) = m / M = 9/18 = 0.5 mol;
4) V (CO) = V (CH4) = 5 L;
5) V (H2) = V (CH4) * 3 = 5 * 3 = 15 liters.

Answer: The CO volume is 5 liters; H2 – 15 HP



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