Calculate the volumes of nitric oxide (IV) and oxygen that will be required to obtain 1 mol of nitric acid.

Given:
n (HNO3) = 1 mol

To find:
V (NO2) -?
V (O2) -?

1) Write the reaction equation:
4NO2 + O2 + 2H2O => 4HNO3;
2) Determine the amount of the substance NO2 (taking into account the coefficients in the reaction equation):
n (NO2) = n (HNO3) = 1 mol;
3) Calculate the volume of NO2:
V (NO2) = n (NO2) * Vm = 1 * 22.4 = 22.4 L;
4) Determine the amount of substance O2 (taking into account the coefficients in the reaction equation):
n (O2) = n (HNO3) / 4 = 1/4 = 0.25 mol;
5) Calculate the volume of O2:
V (O2) = n (O2) * Vm = 0.25 * 22.4 = 5.6 liters.

Answer: The volume of NO2 is 22.4 liters; O2 – 5.6 L