Calculate the volumes of nitrogen and hydrogen required to obtain 33.6 liters of ammonia.

1. Let’s compose the equation of chemical reaction:

N2 + 3H2 = 2NH3.

2. Find the chemical amount of ammonia (Vm – molar volume, constant equal to 22.4 l / mol):

n (NH3) = V (NH3) / Vm = 33.6 L / 22.4 L / mol = 1.5 mol.

3. Using the reaction equation, we find the chemical amount of hydrogen and nitrogen, and then their volumes:

n (N2) = n (NH3) / 2 = 1.5 mol / 2 = 0.75 mol.

V (N2) = n (N2) * Vm = 0.75 mol * 22.4 L / mol = 16.8 L.

n (H2) = n (NH3) / 2 * 3 = 1.5 mol / 2 * 3 = 2.25 mol.

V (H2) = n (H2) * Vm = 2.25 mol * 22.4 l / mol = 50.4 l.

Answer: V (N2) = 16.8 l; V (H2) = 50.4 liters.