Calculate the volumes of oxygen and air required to burn 10 kg of coal, the mass fraction of carbon in which is 90%.

The methane combustion reaction is described by the following chemical reaction equation:

C + O2 = CO2;

Find the mass of pure carbon:

m С = 10,000 x 0.9 = 9,000 grams;

Let’s find the amount of matter in this mass of carbon:

N C = 9,000 / 12 = 750 mol;

To react with this amount of carbon, 750 moles of oxygen are required.

One mole of ideal gas under normal conditions takes up a volume of 22.4 liters.

Calculate the required amount of oxygen

V O2 = 750 x 22.4 = 16 800 liters = 16.8 m3;

The volume fraction of oxygen in the air is 20.95%

The required air volume will be:

V air = 16 800 / 20.95% = 80 191 liter = 80.191 m3;