Calculate the water pressure at the bottom of one of the deepest sea depressions

Calculate the water pressure at the bottom of one of the deepest sea depressions – the Mariana, whose depth is 10,900 m. The density of seawater is 1030 kg / m3.

Given: h = 10900 m
p = 1030 kg / m3
g = 10 N / kg
Find P -?
P = pgh = 1030 • 10 • 10900 = 112270000 Pa = 112.27 MPa
Answer: P = 112.27 MPa



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