Calculate the water pressure at the bottom of one of the deepest sea trenches, the depth

Calculate the water pressure at the bottom of one of the deepest sea trenches, the depth of which is 10,900 m. The density of seawater is 1030 kg / m3.

H = 10 900 m
g = 9.8m / s2 = 10m / s2
ρ = 1030 kg / m3
R-?
The pressure force P is determined by the formula P = ρ * g * N. ρ is the density of the liquid, g is the acceleration of gravity, H is the height of the liquid. P = 1030 kg / m3 * 10 m / s2 * 10900 m = 11237300 N / m2.
Answer: Pressure force P = 11237300 N / m2.