Calculate the work done when the spring is compressed by 0.06 m, if a force of 10N is needed to compress it by 0.01 m.

x1 = 0.06 m.

x2 = 0.01 m.

F2 = 10 N.

A – ?

The work of external forces A when the spring is compressed, according to the law of conservation of energy, is equal to the change in the potential energy of the spring ΔEp: A = ΔEp.

The change in the potential energy of a compressed spring ΔEp is determined by the formula: ΔEp = k * x1 ^ 2/2, where k is the stiffness of the spring, x1 is the change in the length of the spring.

The spring stiffness k is expressed from Hooke’s law by the formula: k = F2 / x2.

The work of external forces will be determined by the formula: A = F2 * x1 ^ 2/2 * x2.

A = 10 H * (0.06 m) ^ 2/2 * 0.01 m = 1.8 J.

Answer: to compress the spring, external forces performed mechanical work A = 1.8 J.

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