Calculate the work of the spring by 2 cm if a force of 80N is needed to stretch it by 2 cm.

x = 2 cm = 0.02 m.

F = 80 N.

A – ?

Mechanical work during deformation of spring A is determined by the formula: A = k * x ^ 2/2, where k is the stiffness of the spring, x is the change in the length of the spring.

According to Hooke’s law, the elastic force F is directly proportional to the change in the length of the spring x: F = k * x.

Let us express the spring stiffness k: k = F / x.

The formula for determining the work will be: A = F * x ^ 2/2 * x = F * x / 2.

A = 80 N * 0.02 m / 2 = 0.8 J.

Answer: when the spring is deformed, it is necessary to perform work A = 0.8 J, the spring, when deformed, does the work Ap = – 0.8 J.