Calculate the yield of nitric oxide 2 if 40 liters of nitrogen oxide2 were obtained in the oxidation reaction of 44.8 liters of NH3.

We carry out the solution:
1. Let us write down the equation and arrange the coefficients:
4NH3 + 5O2 = 4NO + 6H2O – OBP, nitrogen oxide is released (2);
2. Let’s calculate the amount of mol of ammonia, nitrogen oxide NO:
1 mole of gas at normal level – 22.4 liters;
X mol (NH3) – 44.8 liters. hence, X mol (NH3) = 1 * 44.8 / 22.4 = 2 mol;
2 mol (NH3) – X mol (NO);
-4 mol -4 mol from here, X mol (NO) = 2 * 4/4 = 2 mol.
3. Find the theoretical volume of nitric oxide:
V (NO) = 2 * 22.4 = 44.8 liters.
4. Let’s calculate the volumetric yield of the product:
V (practical) / V (theoretical) * 100 = 40 / 44.8 * 100 = 89.28%
Answer: The volumetric yield of the ester was 89.28%.