Calculate what mass of copper can be obtained if 0.5 mol of copper oxide (11) was heated

Calculate what mass of copper can be obtained if 0.5 mol of copper oxide (11) was heated until the end of the reaction in an excess of hydrogen CuO + H2-   Cu + H2O

Divalent copper oxide is reduced with hydrogen gas when heated. This synthesizes metallic copper and water. The reaction is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal (equivalent) molar amounts. In the course of the reaction, the same equal chemical amounts of copper and water are synthesized.

N CuO = 64/80 = 0.5 mol;

Thus, it is necessary to reduce 0.5 mol of copper oxide and synthesize 0.5 mol of copper.

Its weight will be:

M Cu = 64 grams / mol;

m Cu = 64 x 0.5 = 32 grams;