Calculate what mass of magnesium hydroxide will precipitate when a magnesium chloride solution

Calculate what mass of magnesium hydroxide will precipitate when a magnesium chloride solution interacts with a solution containing 0.1 mol of sodium hydroxide?

Given:
n (NaOH) = 0.1 mol
To find:
m (Mg (OH) 2)
Decision:
MgCl2 + 2NaOH = Mg (OH) 2 + 2NaCl
n (NaOH): n (Mg (OH) 2) = 2: 1
n (Mg (OH) 2) = 0.1 mol / 2 = 0.05 mol
m (Mg (OH) 2) = n * M = 0.05 mol * 58 g / mol = 11.6 g
Answer: 11.6 g



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