Calculate what mass of oxide is formed by the interaction of oxygen with calcium weighing 1.6 g.

1. Let’s compose the equation of interaction:

2Ca + O2 = 2CaO;

2. find the chemical amount of calcium:

n (Ca) = m (Ca): M (Ca) = 1.6: 40 = 0.04 mol;

3.Calculate the amount and mass of calcium oxide:

n (CaO) = n (Ca) = 0.04 mol;

m (CaO) = n (CaO) * M (CaO);

M (CaO) = 40 + 16 = 56 g / mol;

m (CaO) = 0.04 * 56 = 2.24 g.

Answer: 2.24 g.