Calculate what mass of phosphorus oxide (v) interacts with water, if the result is orthophosphoric acid weighing 9.8 g.?

Given:
m (H3PO4) = 9.8 g
Find: m (P2O5)
Decision:
M (P2O5) = 31 * 2 + 16 * 5 = 142 g / mol
M (H3PO4) = 1 * 3 + 31 + 16 * 4 = 98 g / mol
The mass of phosphorus oxide is easy to find through the proportion:
x / 142 = 9.8 / 98
x = 14.2 g



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