Calculate what mass of salt can be obtained practically by the interaction of 200 g – 20% solution (NaOH) with HCl.

1. Let’s compose the equation of the chemical reaction:

NaOH + HCl = NaCl + H2O.

2. Find the chemical amount of the reacted sodium hydroxide:

m (NaOH) = m (solution) * ω (NaOH) / 100% = 200 g * 20% / 100% = 40 g.

n (NaOH) = m (NaOH) / M (NaOH) = 40 g / 40 g / mol = 1 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of the released sodium chloride:

n (NaCl) = n (NaOH) = 1 mol.

m (NaCl) = n (NaCl) * M (NaCl) = 1 mol * 58.5 g / mol = 58.5 g.

Answer: m (NaCl) = 58.5 g.