Calculate what mass of sodium ethylate is formed by the interaction of metallic sodium with 45 g of 96% ethyl alcohol.

1. Let’s compose the equation of the chemical reaction:

2C2H5OH + 2Na = 2C2H5ONa + H2.

2. Find the chemical amount of the reacted ethyl alcohol:

m (C2H5OH) = m (solution) * ω (C2H5OH) / 100% = 45 g * 96% / 100% = 43.2 g.

n (C2H5OH) = m (C2H5OH) / M (C2H5OH) = 43.2 g / 46 g / mol = 0.94 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of sodium ethylate:

n (C2H5ONa) = n (C2H5OH) = 0.94 mol.

m (C2H5ONa) = n (C2H5ONa) * M (C2H5ONa) = 0.94 mol * 68 g / mol = 63.86 g.

Answer: m (C2H5ONa) = 63.86 g.