Calculate what volume of carbon monoxide (4) is formed during combustion of 0.25 mol of sucrose.

C12H22O11 + 12O2 = 12CO2 + 11H2O.

First, we determine how much of a substance of carbon monoxide is formed from 0.25 mol of sucrose, taking into account the reaction that 12 mol of carbon monoxide is formed from 1 mol of sucrose:

0.25 mol – x mol

1 mol – 12 mol.

From here we find that x = 12 * 0.25 = 3 mol – the amount of substance CO2.

Knowing that 1 mole of any gas under normal conditions. occupies a volume equal to 22.4 liters, we find the volume of carbon monoxide:

V = 3 * 22.4 = 67.2 l.