Calculate what volume will take a) 38 g of chlorine b) 0.4 mol of chlorine c) 1.5 mol of oxygen?

a) Given:
m (Cl2) = 38 g
To find:
V (Cl2) =?
Decision:
m / M = V / Vm
M (Cl2) = 35.5 x 2 = 70 g / mol
V (Cl20 = (38 g x 22.4 L / mol): 70 g / mol = 12.16 L.
Answer: V (Cl2) = 12.16 liters.

b) Given:
n (Cl2) = 0.4 mol
To find:
V (Cl2) =?
Decision:
n = V / Vm, hence V = n x Vm
V (Cl2) = 0.4 mol x 22.4 L / mol = 8.96 L.
Answer: V (Cl2) = 8, 96 liters.

c) Given:
n (O2) = 1.5 mol
To find:
V (O2) =?
Decision:
V = n x Vm
V (O2) = 1.5 mol x 22.4 L / mol = 33.6 L.
Answer: V (O2) = 33.6 liters.
* Vm is a constant value and is equal to 22.4 l / mol.