Calculate whether 224 liters of hydrogen will be enough for the complete reduction of iron from iron (III) oxide
Calculate whether 224 liters of hydrogen will be enough for the complete reduction of iron from iron (III) oxide obtained as a result of thermal decomposition of iron (III) hydroxide weighing 428 g.
1. Let’s compose the equations of chemical reactions:
2Fe (OH) 3 = Fe2O3 + 3H2O.
Fe2O3 + 3H2 = 2Fe + 3H2O.
2. Find the chemical amount of iron hydroxide and hydrogen (Vm – molar volume, constant equal to 22.4 l / mol):
n (Fe (OH) 3) = m (Fe (OH) 3) / M (Fe (OH) 3) = 428 g / 107 g / mol = 4 mol.
n (H2) = V (H2) / Vm = 224 L / 22.4 L / mol = 10 mol.
3. According to the reaction equation, we find the chemical amount of hydrogen required to obtain a given amount of iron:
n (H2) = n (Fe (OH) 3) / 2 * 3 = 4 mol / 2 * 3 = 6 mol.
Hence, 10 moles of hydrogen is sufficient.
Answer: enough.