Calculate with what amount of hydrochloric acid (in moles) 0.1 mole of aluminum can react.

1. Let’s compose the equation of the reaction between aluminum and hydrochloric acid.
2 Al + 6 HCl = 2AlCl3 + 3H2.
Using the reaction equation, we determine in what proportions hydrochloric acid and aluminum react.
2 mol of aluminum reacts with 6 mol of hydrochloric acid, that is, they are in a ratio of 2: 6 (1: 3).
2.Calculate the amount of hydrochloric acid substance if 0.1 mol of aluminum entered the reaction.
Let’s make a proportion.
2 mol (Al) – 6 mol (HCl),
0.1 mol (Al) – х mol (HCl),
x mol (HCl) = (0.1 mol × 6 mol): 2 mol = 0.3 mol.
Answer: n (HCl) = 0.3 mol.



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