Calculation of the mass of the product from the known mass of the starting material

Calculation of the mass of the product from the known mass of the starting material. (How many grams of copper sulfate was formed by the interaction of 100 kg of copper oxide (2) with sulfuric acid?)

1. Let’s compose the uranium of the interaction of copper oxide with sulfuric acid:

CuO + H2SO4 = CuSO4 + H2O;

2. Determine the chemical amount of copper oxide:

n (CuO) = m (CuO): M (CuO);

M (CuO) = 64 + 16 = 80 g / mol;

n (CuO) = 100: 80 = 1.25 kmol;

3. Set the amount of copper sulfate obtained:

n (CuSO4) = n (CuO) = 1.25 kmol;

4. Let’s calculate the mass of the obtained salt:

m (CuSO4) = n (CuSO4) * M (CuSO4);

M (CuSO4) = 64 + 32 + 4 * 16 = 160 g / mol;

m (CuSO4) = 1.25 * 160 = 200 kg.

Answer: 200 kg.



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