Can a bullet weighing 10g pierce a 60cm thick board, initial velocity V = 600m) s, and resistance force V = 3800N.

For a bullet to be able to penetrate the taken board, the inequality must be fulfilled: hd ≤ Sп; hd ≤ A / F; hd ≤ (m * V ^ 2/2) / F.

Values of variables: hd – thickness of the board taken (hd = 60 cm = 0.6 m); m is the mass of the bullet (m = 10 g = 0.01 kg); V is the initial velocity of the bullet (V = 600 m / s); F is the resistance force of the board (F = 3800 N).

Calculation: hd ≤ (m * V ^ 2/2) / F.

0.6 ≤ (0.01 * 600 ^ 2/2) / 3800.

0.6 ≤ 0.5 (incorrect).

Answer: The bullet will not penetrate the taken board.



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