Car tires have air under a pressure of 6 * 10 ^ 5 at a temperature of 293K. While the car is moving, the air temperature

Car tires have air under a pressure of 6 * 10 ^ 5 at a temperature of 293K. While the car is moving, the air temperature rises to 308K. How much does the air pressure inside the tire increase? The volume is considered constant

To find out the change in air pressure inside the tire under consideration, we use the formula: ΔР = Рк – Рн = Рн * Тк / Тн – Рн = Рн * (Тк / Тн – 1).

These tasks: Рн – initial pressure in the tire (Рн = 6 * 10 ^ 5 Pa); Тк – final air temperature (Тк = 308 К); Тн – initial air temperature (Тн = 293 К).

Let’s perform the calculation: ΔР = Рн * (Тк / Тн – 1) = 6 * 10 ^ 5 * (308/293 – 1) ≈ 30.72 * 10 ^ 3 Pa.

Answer: The pressure inside the tire in question should have increased by 30.72 kPa.